4(2+2)+6(y+2)=48

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Solution for 4(2+2)+6(y+2)=48 equation: 



4(2+2)+6(y+2)=48

We move all terms to the left:

4(2+2)+6(y+2)-(48)=0

determiningTheFunctionDomain
6(y+2)-48+4(2+2)=0

We add all the numbers together, and all the variables

6(y+2)-48+44=0

We add all the numbers together, and all the variables

6(y+2)-4=0

We multiply parentheses

6y+12-4=0

We add all the numbers together, and all the variables

6y+8=0

We move all terms containing y to the left, all other terms to the right

6y=-8

y=-8/6

y=-1+1/3

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