4(1y+-8)=12

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Solution for 4(1y+-8)=12 equation:



4(1y+-8)=12
We move all terms to the left:
4(1y+-8)-(12)=0
We add all the numbers together, and all the variables
4(y-8)-12=0
We multiply parentheses
4y-32-12=0
We add all the numbers together, and all the variables
4y-44=0
We move all terms containing y to the left, all other terms to the right
4y=44
y=44/4
y=11

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