4(1x-2)=8(1x-3)-12

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Solution for 4(1x-2)=8(1x-3)-12 equation: 



4(1x-2)=8(1x-3)-12

We move all terms to the left:

4(1x-2)-(8(1x-3)-12)=0

We add all the numbers together, and all the variables

4(x-2)-(8(x-3)-12)=0

We multiply parentheses

4x-(8(x-3)-12)-8=0



We calculate terms in parentheses: -(8(x-3)-12), so:

8(x-3)-12

We multiply parentheses

8x-24-12

We add all the numbers together, and all the variables

8x-36

Back to the equation:

-(8x-36)



We get rid of parentheses

4x-8x+36-8=0

We add all the numbers together, and all the variables

-4x+28=0

We move all terms containing x to the left, all other terms to the right

-4x=-28

x=-28/-4

x=+7

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