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4(1x+1)+x=5(1x-1)+9
We move all terms to the left:
4(1x+1)+x-(5(1x-1)+9)=0
We add all the numbers together, and all the variables
4(x+1)+x-(5(x-1)+9)=0
We add all the numbers together, and all the variables
x+4(x+1)-(5(x-1)+9)=0
We multiply parentheses
x+4x-(5(x-1)+9)+4=0
We calculate terms in parentheses: -(5(x-1)+9), so:We add all the numbers together, and all the variables
5(x-1)+9
We multiply parentheses
5x-5+9
We add all the numbers together, and all the variables
5x+4
Back to the equation:
-(5x+4)
5x-(5x+4)+4=0
We get rid of parentheses
5x-5x-4+4=0
We add all the numbers together, and all the variables
=0
x=0/1
x=0
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