4(1c)=3c+1c+2-2

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Solution for 4(1c)=3c+1c+2-2 equation: 



4(1c)=3c+1c+2-2

We move all terms to the left:

4(1c)-(3c+1c+2-2)=0

We add all the numbers together, and all the variables

41c-(+4c)=0

We get rid of parentheses

41c-4c=0

We add all the numbers together, and all the variables

37c=0

c=0/37

c=0

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