4(10+b)=-8(b+1)

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Solution for 4(10+b)=-8(b+1) equation:


Simplifying
4(10 + b) = -8(b + 1)
(10 * 4 + b * 4) = -8(b + 1)
(40 + 4b) = -8(b + 1)

Reorder the terms:
40 + 4b = -8(1 + b)
40 + 4b = (1 * -8 + b * -8)
40 + 4b = (-8 + -8b)

Solving
40 + 4b = -8 + -8b

Solving for variable 'b'.

Move all terms containing b to the left, all other terms to the right.

Add '8b' to each side of the equation.
40 + 4b + 8b = -8 + -8b + 8b

Combine like terms: 4b + 8b = 12b
40 + 12b = -8 + -8b + 8b

Combine like terms: -8b + 8b = 0
40 + 12b = -8 + 0
40 + 12b = -8

Add '-40' to each side of the equation.
40 + -40 + 12b = -8 + -40

Combine like terms: 40 + -40 = 0
0 + 12b = -8 + -40
12b = -8 + -40

Combine like terms: -8 + -40 = -48
12b = -48

Divide each side by '12'.
b = -4

Simplifying
b = -4

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