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4(1/2)+y=10(1/20
We move all terms to the left:
4(1/2)+y-(10(1/20)=0
We add all the numbers together, and all the variables
y+4(+1/2)-(10(+1/20)=0
We add all the numbers together, and all the variables
y-(10(+1/20)+2=0
We multiply all the terms by the denominator
y*20)+2-(10(+1=0
Wy multiply elements
20y^2=0
a = 20; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·20·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation
Stosujemy wzór:$y=\frac{-b}{2a}=\frac{0}{40}=0$
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