4(1-x)=8x-5(x+2)

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Solution for 4(1-x)=8x-5(x+2) equation: 



4(1-x)=8x-5(x+2)

We move all terms to the left:

4(1-x)-(8x-5(x+2))=0

We add all the numbers together, and all the variables

4(-1x+1)-(8x-5(x+2))=0

We multiply parentheses

-4x-(8x-5(x+2))+4=0



We calculate terms in parentheses: -(8x-5(x+2)), so:

8x-5(x+2)

We multiply parentheses

8x-5x-10

We add all the numbers together, and all the variables

3x-10

Back to the equation:

-(3x-10)



We get rid of parentheses

-4x-3x+10+4=0

We add all the numbers together, and all the variables

-7x+14=0

We move all terms containing x to the left, all other terms to the right

-7x=-14

x=-14/-7

x=+2

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