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4(1-x)+3x=-2x^2
We move all terms to the left:
4(1-x)+3x-(-2x^2)=0
We add all the numbers together, and all the variables
-(-2x^2)+4(-1x+1)+3x=0
We add all the numbers together, and all the variables
-(-2x^2)+3x+4(-1x+1)=0
We multiply parentheses
-(-2x^2)+3x-4x+4=0
We get rid of parentheses
2x^2+3x-4x+4=0
We add all the numbers together, and all the variables
2x^2-1x+4=0
a = 2; b = -1; c = +4;
Δ = b2-4ac
Δ = -12-4·2·4
Δ = -31
Delta is less than zero, so there is no solution for the equation
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