4(1-3n)-8n=-2(n-2)

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Solution for 4(1-3n)-8n=-2(n-2) equation: 



4(1-3n)-8n=-2(n-2)

We move all terms to the left:

4(1-3n)-8n-(-2(n-2))=0

We add all the numbers together, and all the variables

4(-3n+1)-8n-(-2(n-2))=0

We add all the numbers together, and all the variables

-8n+4(-3n+1)-(-2(n-2))=0

We multiply parentheses

-8n-12n-(-2(n-2))+4=0



We calculate terms in parentheses: -(-2(n-2)), so:

-2(n-2)

We multiply parentheses

-2n+4

Back to the equation:

-(-2n+4)



We add all the numbers together, and all the variables

-20n-(-2n+4)+4=0

We get rid of parentheses

-20n+2n-4+4=0

We add all the numbers together, and all the variables

-18n=0

n=0/-18

n=0

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