4(1-2b)+7b-10=48

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Solution for 4(1-2b)+7b-10=48 equation: 



4(1-2b)+7b-10=48

We move all terms to the left:

4(1-2b)+7b-10-(48)=0

We add all the numbers together, and all the variables

4(-2b+1)+7b-10-48=0

We add all the numbers together, and all the variables

7b+4(-2b+1)-58=0

We multiply parentheses

7b-8b+4-58=0

We add all the numbers together, and all the variables

-1b-54=0

We move all terms containing b to the left, all other terms to the right

-b=54

b=54/-1

b=-54

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