4(1-1x)+3x=2(1x+1)

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Solution for 4(1-1x)+3x=2(1x+1) equation:



4(1-1x)+3x=2(1x+1)
We move all terms to the left:
4(1-1x)+3x-(2(1x+1))=0
We add all the numbers together, and all the variables
4(-1x+1)+3x-(2(x+1))=0
We add all the numbers together, and all the variables
3x+4(-1x+1)-(2(x+1))=0
We multiply parentheses
3x-4x-(2(x+1))+4=0
We calculate terms in parentheses: -(2(x+1)), so:
2(x+1)
We multiply parentheses
2x+2
Back to the equation:
-(2x+2)
We add all the numbers together, and all the variables
-1x-(2x+2)+4=0
We get rid of parentheses
-1x-2x-2+4=0
We add all the numbers together, and all the variables
-3x+2=0
We move all terms containing x to the left, all other terms to the right
-3x=-2
x=-2/-3
x=2/3

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