4(1+y)=7(y-2)

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Solution for 4(1+y)=7(y-2) equation: 



4(1+y)=7(y-2)

We move all terms to the left:

4(1+y)-(7(y-2))=0

We add all the numbers together, and all the variables

4(y+1)-(7(y-2))=0

We multiply parentheses

4y-(7(y-2))+4=0



We calculate terms in parentheses: -(7(y-2)), so:

7(y-2)

We multiply parentheses

7y-14

Back to the equation:

-(7y-14)



We get rid of parentheses

4y-7y+14+4=0

We add all the numbers together, and all the variables

-3y+18=0

We move all terms containing y to the left, all other terms to the right

-3y=-18

y=-18/-3

y=+6

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