4(1+c)-(3+c)=15

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Solution for 4(1+c)-(3+c)=15 equation:


Simplifying
4(1 + c) + -1(3 + c) = 15
(1 * 4 + c * 4) + -1(3 + c) = 15
(4 + 4c) + -1(3 + c) = 15
4 + 4c + (3 * -1 + c * -1) = 15
4 + 4c + (-3 + -1c) = 15

Reorder the terms:
4 + -3 + 4c + -1c = 15

Combine like terms: 4 + -3 = 1
1 + 4c + -1c = 15

Combine like terms: 4c + -1c = 3c
1 + 3c = 15

Solving
1 + 3c = 15

Solving for variable 'c'.

Move all terms containing c to the left, all other terms to the right.

Add '-1' to each side of the equation.
1 + -1 + 3c = 15 + -1

Combine like terms: 1 + -1 = 0
0 + 3c = 15 + -1
3c = 15 + -1

Combine like terms: 15 + -1 = 14
3c = 14

Divide each side by '3'.
c = 4.666666667

Simplifying
c = 4.666666667

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