4(1+2p)=(p-5)-4

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Solution for 4(1+2p)=(p-5)-4 equation: 



4(1+2p)=(p-5)-4

We move all terms to the left:

4(1+2p)-((p-5)-4)=0

We add all the numbers together, and all the variables

4(2p+1)-((p-5)-4)=0

We multiply parentheses

8p-((p-5)-4)+4=0



We calculate terms in parentheses: -((p-5)-4), so:

(p-5)-4

We get rid of parentheses

p-5-4

We add all the numbers together, and all the variables

p-9

Back to the equation:

-(p-9)



We get rid of parentheses

8p-p+9+4=0

We add all the numbers together, and all the variables

7p+13=0

We move all terms containing p to the left, all other terms to the right

7p=-13

p=-13/7

p=-1+6/7

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