4(1+2b)=20+4b

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Solution for 4(1+2b)=20+4b equation: 



4(1+2b)=20+4b

We move all terms to the left:

4(1+2b)-(20+4b)=0

We add all the numbers together, and all the variables

4(2b+1)-(4b+20)=0

We multiply parentheses

8b-(4b+20)+4=0

We get rid of parentheses

8b-4b-20+4=0

We add all the numbers together, and all the variables

4b-16=0

We move all terms containing b to the left, all other terms to the right

4b=16

b=16/4

b=4

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