4(05n-3)=n-025(12-8n)

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Solution for 4(05n-3)=n-025(12-8n) equation:



4(05n-3)=n-025(12-8n)
We move all terms to the left:
4(05n-3)-(n-025(12-8n))=0
We add all the numbers together, and all the variables
4(05n-3)-(n-025(-8n+12))=0
We multiply parentheses
20n-(n-025(-8n+12))-12=0
We calculate terms in parentheses: -(n-025(-8n+12)), so:
n-025(-8n+12)
We multiply parentheses
n+200n-300
We add all the numbers together, and all the variables
201n-300
Back to the equation:
-(201n-300)
We get rid of parentheses
20n-201n+300-12=0
We add all the numbers together, and all the variables
-181n+288=0
We move all terms containing n to the left, all other terms to the right
-181n=-288
n=-288/-181
n=1+107/181

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