4(-z+4)=2

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Solution for 4(-z+4)=2 equation: 



4(-z+4)=2

We move all terms to the left:

4(-z+4)-(2)=0

We add all the numbers together, and all the variables

4(-1z+4)-2=0

We multiply parentheses

-4z+16-2=0

We add all the numbers together, and all the variables

-4z+14=0

We move all terms containing z to the left, all other terms to the right

-4z=-14

z=-14/-4

z=3+1/2

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