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4(-x-2)(-x-2)=16
We move all terms to the left:
4(-x-2)(-x-2)-(16)=0
We add all the numbers together, and all the variables
4(-1x-2)(-1x-2)-16=0
We multiply parentheses ..
4(+x^2+2x+2x+4)-16=0
We multiply parentheses
4x^2+8x+8x+16-16=0
We add all the numbers together, and all the variables
4x^2+16x=0
a = 4; b = 16; c = 0;
Δ = b2-4ac
Δ = 162-4·4·0
Δ = 256
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{256}=16$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(16)-16}{2*4}=\frac{-32}{8} =-4 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(16)+16}{2*4}=\frac{0}{8} =0 $
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