4(-7/2b+3)=129/2

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Solution for 4(-7/2b+3)=129/2 equation: 



4(-7/2b+3)=129/2

We move all terms to the left:

4(-7/2b+3)-(129/2)=0



Domain of the equation: 2b+3)!=0

b∈R



We add all the numbers together, and all the variables

4(-7/2b+3)-(+129/2)=0

We multiply parentheses

-28b+12-(+129/2)=0

We get rid of parentheses

-28b+12-129/2=0

We multiply all the terms by the denominator


-28b*2-129+12*2=0

We add all the numbers together, and all the variables

-28b*2-105=0

Wy multiply elements

-56b-105=0

We move all terms containing b to the left, all other terms to the right

-56b=105

b=105/-56

b=-1+7/8

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