4(-7+4k)=5(2k-2)

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Solution for 4(-7+4k)=5(2k-2) equation: 



4(-7+4k)=5(2k-2)

We move all terms to the left:

4(-7+4k)-(5(2k-2))=0

We add all the numbers together, and all the variables

4(4k-7)-(5(2k-2))=0

We multiply parentheses

16k-(5(2k-2))-28=0



We calculate terms in parentheses: -(5(2k-2)), so:

5(2k-2)

We multiply parentheses

10k-10

Back to the equation:

-(10k-10)



We get rid of parentheses

16k-10k+10-28=0

We add all the numbers together, and all the variables

6k-18=0

We move all terms containing k to the left, all other terms to the right

6k=18

k=18/6

k=3

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