4(-7+3x)=68

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Solution for 4(-7+3x)=68 equation: 



4(-7+3x)=68

We move all terms to the left:

4(-7+3x)-(68)=0

We add all the numbers together, and all the variables

4(3x-7)-68=0

We multiply parentheses

12x-28-68=0

We add all the numbers together, and all the variables

12x-96=0

We move all terms containing x to the left, all other terms to the right

12x=96

x=96/12

x=8

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