4(-3x-2)=8+3(x-2)

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Solution for 4(-3x-2)=8+3(x-2) equation: 



4(-3x-2)=8+3(x-2)

We move all terms to the left:

4(-3x-2)-(8+3(x-2))=0

We multiply parentheses

-12x-(8+3(x-2))-8=0



We calculate terms in parentheses: -(8+3(x-2)), so:

8+3(x-2)

determiningTheFunctionDomain
3(x-2)+8

We multiply parentheses

3x-6+8

We add all the numbers together, and all the variables

3x+2

Back to the equation:

-(3x+2)



We get rid of parentheses

-12x-3x-2-8=0

We add all the numbers together, and all the variables

-15x-10=0

We move all terms containing x to the left, all other terms to the right

-15x=10

x=10/-15

x=-2/3

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