4(-2x-5)-3(x+4)=8(2x-1)-6

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Solution for 4(-2x-5)-3(x+4)=8(2x-1)-6 equation: 



4(-2x-5)-3(x+4)=8(2x-1)-6

We move all terms to the left:

4(-2x-5)-3(x+4)-(8(2x-1)-6)=0

We multiply parentheses

-8x-3x-(8(2x-1)-6)-20-12=0



We calculate terms in parentheses: -(8(2x-1)-6), so:

8(2x-1)-6

We multiply parentheses

16x-8-6

We add all the numbers together, and all the variables

16x-14

Back to the equation:

-(16x-14)



We add all the numbers together, and all the variables

-11x-(16x-14)-32=0

We get rid of parentheses

-11x-16x+14-32=0

We add all the numbers together, and all the variables

-27x-18=0

We move all terms containing x to the left, all other terms to the right

-27x=18

x=18/-27

x=-2/3

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