3z/7+6=1

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Solution for 3z/7+6=1 equation: 



3z/7+6=1

We move all terms to the left:

3z/7+6-(1)=0

We add all the numbers together, and all the variables

3z/7+5=0

We multiply all the terms by the denominator


3z+5*7=0

We add all the numbers together, and all the variables

3z+35=0

We move all terms containing z to the left, all other terms to the right

3z=-35

z=-35/3

z=-11+2/3

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