3z-5(3z+2)=2-5(-4-z)

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Solution for 3z-5(3z+2)=2-5(-4-z) equation: 



3z-5(3z+2)=2-5(-4-z)

We move all terms to the left:

3z-5(3z+2)-(2-5(-4-z))=0

We add all the numbers together, and all the variables

3z-5(3z+2)-(2-5(-1z-4))=0

We multiply parentheses

3z-15z-(2-5(-1z-4))-10=0



We calculate terms in parentheses: -(2-5(-1z-4)), so:

2-5(-1z-4)

determiningTheFunctionDomain
-5(-1z-4)+2

We multiply parentheses

5z+20+2

We add all the numbers together, and all the variables

5z+22

Back to the equation:

-(5z+22)



We add all the numbers together, and all the variables

-12z-(5z+22)-10=0

We get rid of parentheses

-12z-5z-22-10=0

We add all the numbers together, and all the variables

-17z-32=0

We move all terms containing z to the left, all other terms to the right

-17z=32

z=32/-17

z=-1+15/17

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