3z-4(z+1)=(6z+4)+z

Solution for 3z-4(z+1)=(6z+4)+z equation:

Simplifying
3z + -4(z + 1) = (6z + 4) + z

Reorder the terms:
3z + -4(1 + z) = (6z + 4) + z
3z + (1 * -4 + z * -4) = (6z + 4) + z
3z + (-4 + -4z) = (6z + 4) + z

Reorder the terms:
-4 + 3z + -4z = (6z + 4) + z

Combine like terms: 3z + -4z = -1z
-4 + -1z = (6z + 4) + z

Reorder the terms:
-4 + -1z = (4 + 6z) + z

Remove parenthesis around (4 + 6z)
-4 + -1z = 4 + 6z + z

Combine like terms: 6z + z = 7z
-4 + -1z = 4 + 7z

Solving
-4 + -1z = 4 + 7z

Solving for variable 'z'.

Move all terms containing z to the left, all other terms to the right.

Add '-7z' to each side of the equation.
-4 + -1z + -7z = 4 + 7z + -7z

Combine like terms: -1z + -7z = -8z
-4 + -8z = 4 + 7z + -7z

Combine like terms: 7z + -7z = 0
-4 + -8z = 4 + 0
-4 + -8z = 4

Add '4' to each side of the equation.
-4 + 4 + -8z = 4 + 4

Combine like terms: -4 + 4 = 0
0 + -8z = 4 + 4
-8z = 4 + 4

Combine like terms: 4 + 4 = 8
-8z = 8

Divide each side by '-8'.
z = -1

Simplifying
z = -1