3z-22=4(2-3z)

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Solution for 3z-22=4(2-3z) equation: 



3z-22=4(2-3z)

We move all terms to the left:

3z-22-(4(2-3z))=0

We add all the numbers together, and all the variables

3z-(4(-3z+2))-22=0



We calculate terms in parentheses: -(4(-3z+2)), so:

4(-3z+2)

We multiply parentheses

-12z+8

Back to the equation:

-(-12z+8)



We get rid of parentheses

3z+12z-8-22=0

We add all the numbers together, and all the variables

15z-30=0

We move all terms containing z to the left, all other terms to the right

15z=30

z=30/15

z=2

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