3z-17/3=2z/3-3/2

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Solution for 3z-17/3=2z/3-3/2 equation: 


z in (-oo:+oo)

3*z-(17/3) = (2*z)/3-(3/2) // - (2*z)/3-(3/2)

3*z-((2*z)/3)-(17/3)+3/2 = 0

3*z+(-2/3)*z-17/3+3/2 = 0

7/3*z-25/6 = 0 // + 25/6

7/3*z = 25/6 // : 7/3

z = 25/6/7/3

z = 25/14

z = 25/14

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