3z-(z-4)=12

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Solution for 3z-(z-4)=12 equation:


Simplifying
3z + -1(z + -4) = 12

Reorder the terms:
3z + -1(-4 + z) = 12
3z + (-4 * -1 + z * -1) = 12
3z + (4 + -1z) = 12

Reorder the terms:
4 + 3z + -1z = 12

Combine like terms: 3z + -1z = 2z
4 + 2z = 12

Solving
4 + 2z = 12

Solving for variable 'z'.

Move all terms containing z to the left, all other terms to the right.

Add '-4' to each side of the equation.
4 + -4 + 2z = 12 + -4

Combine like terms: 4 + -4 = 0
0 + 2z = 12 + -4
2z = 12 + -4

Combine like terms: 12 + -4 = 8
2z = 8

Divide each side by '2'.
z = 4

Simplifying
z = 4

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