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3z+5/2z+1=1/3
We move all terms to the left:
3z+5/2z+1-(1/3)=0
Domain of the equation: 2z!=0We add all the numbers together, and all the variables
z!=0/2
z!=0
z∈R
3z+5/2z+1-(+1/3)=0
We get rid of parentheses
3z+5/2z+1-1/3=0
We calculate fractions
There is no solution for this equation
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