3z+2(z-5)=35

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Solution for 3z+2(z-5)=35 equation: 



3z+2(z-5)=35

We move all terms to the left:

3z+2(z-5)-(35)=0

We multiply parentheses

3z+2z-10-35=0

We add all the numbers together, and all the variables

5z-45=0

We move all terms containing z to the left, all other terms to the right

5z=45

z=45/5

z=9

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