3z+18(2+1)=60

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Solution for 3z+18(2+1)=60 equation: 



3z+18(2+1)=60

We move all terms to the left:

3z+18(2+1)-(60)=0

determiningTheFunctionDomain
3z-60+18(2+1)=0

We add all the numbers together, and all the variables

3z-60+183=0

We add all the numbers together, and all the variables

3z+123=0

We move all terms containing z to the left, all other terms to the right

3z=-123

z=-123/3

z=-41

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