3z+1/8=4z+7/8

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Solution for 3z+1/8=4z+7/8 equation: 



3z+1/8=4z+7/8

We move all terms to the left:

3z+1/8-(4z+7/8)=0

We add all the numbers together, and all the variables

3z-(+4z+7/8)+1/8=0

We get rid of parentheses

3z-4z-7/8+1/8=0

We multiply all the terms by the denominator


3z*8-4z*8-7+1=0

We add all the numbers together, and all the variables

3z*8-4z*8-6=0

Wy multiply elements

24z-32z-6=0

We add all the numbers together, and all the variables

-8z-6=0

We move all terms containing z to the left, all other terms to the right

-8z=6

z=6/-8

z=-3/4

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