3z+1/4z=6z+1/8z-1

Solution for 3z+1/4z=6z+1/8z-1 equation:

3z+1/4z=6z+1/8z-1

We move all terms to the left:

3z+1/4z-(6z+1/8z-1)=0


Domain of the equation: 4z!=0

z!=0/4

z!=0

z∈R



Domain of the equation: 8z-1)!=0

z∈R


We get rid of parentheses

3z+1/4z-6z-1/8z+1=0

We calculate fractions


3z-6z+8z/32z^2+(-4z)/32z^2+1=0

We add all the numbers together, and all the variables

-3z+8z/32z^2+(-4z)/32z^2+1=0

We multiply all the terms by the denominator


-3z*32z^2+8z+(-4z)+1*32z^2=0

We add all the numbers together, and all the variables

8z-3z*32z^2+(-4z)+1*32z^2=0

Wy multiply elements

-96z^3+32z^2+8z+(-4z)=0

We get rid of parentheses

-96z^3+32z^2+8z-4z=0

We do not support ezpression: z^3