3z+(5-z)=-(z-1)+1

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Solution for 3z+(5-z)=-(z-1)+1 equation: 



3z+(5-z)=-(z-1)+1

We move all terms to the left:

3z+(5-z)-(-(z-1)+1)=0

We add all the numbers together, and all the variables

3z+(-1z+5)-(-(z-1)+1)=0

We get rid of parentheses

3z-1z-(-(z-1)+1)+5=0



We calculate terms in parentheses: -(-(z-1)+1), so:

-(z-1)+1

We get rid of parentheses

-z+1+1

We add all the numbers together, and all the variables

-1z+2

Back to the equation:

-(-1z+2)



We add all the numbers together, and all the variables

2z-(-1z+2)+5=0

We get rid of parentheses

2z+1z-2+5=0

We add all the numbers together, and all the variables

3z+3=0

We move all terms containing z to the left, all other terms to the right

3z=-3

z=-3/3

z=-1

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