3y=(7y-2)+5y-22

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Solution for 3y=(7y-2)+5y-22 equation: 



3y=(7y-2)+5y-22

We move all terms to the left:

3y-((7y-2)+5y-22)=0



We calculate terms in parentheses: -((7y-2)+5y-22), so:

(7y-2)+5y-22

We add all the numbers together, and all the variables

5y+(7y-2)-22

We get rid of parentheses

5y+7y-2-22

We add all the numbers together, and all the variables

12y-24

Back to the equation:

-(12y-24)



We get rid of parentheses

3y-12y+24=0

We add all the numbers together, and all the variables

-9y+24=0

We move all terms containing y to the left, all other terms to the right

-9y=-24

y=-24/-9

y=2+2/3

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