3y2=5y+5

Solution for 3y2=5y+5 equation:

3y^2=5y+5

We move all terms to the left:

3y^2-(5y+5)=0

We get rid of parentheses

3y^2-5y-5=0

a = 3; b = -5; c = -5;
Δ = b2-4ac
Δ = -52-4·3·(-5)
Δ = 85
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-5)-\sqrt{85}}{2*3}=\frac{5-\sqrt{85}}{6}
$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-5)+\sqrt{85}}{2*3}=\frac{5+\sqrt{85}}{6}
$