3y2-5y-18=(3y+2)(y-3)

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Solution for 3y2-5y-18=(3y+2)(y-3) equation: 



3y^2-5y-18=(3y+2)(y-3)

We move all terms to the left:

3y^2-5y-18-((3y+2)(y-3))=0

We multiply parentheses ..

3y^2-((+3y^2-9y+2y-6))-5y-18=0



We calculate terms in parentheses: -((+3y^2-9y+2y-6)), so:

(+3y^2-9y+2y-6)

We get rid of parentheses

3y^2-9y+2y-6

We add all the numbers together, and all the variables

3y^2-7y-6

Back to the equation:

-(3y^2-7y-6)



We add all the numbers together, and all the variables

3y^2-5y-(3y^2-7y-6)-18=0

We get rid of parentheses

3y^2-3y^2-5y+7y+6-18=0

We add all the numbers together, and all the variables

2y-12=0

We move all terms containing y to the left, all other terms to the right

2y=12

y=12/2

y=6

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