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3y/5-9/5(3y-5)=y-1
We move all terms to the left:
3y/5-9/5(3y-5)-(y-1)=0
Domain of the equation: 5(3y-5)!=0We get rid of parentheses
y∈R
3y/5-9/5(3y-5)-y+1=0
We calculate fractions
-y+1=0
We add all the numbers together, and all the variables
-1y+1=0
We move all terms containing y to the left, all other terms to the right
-y=-1
y=-1/-1
y=1
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