3y-9+3(4y+3)=-3(y+1)

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Solution for 3y-9+3(4y+3)=-3(y+1) equation: 



3y-9+3(4y+3)=-3(y+1)

We move all terms to the left:

3y-9+3(4y+3)-(-3(y+1))=0

We multiply parentheses

3y+12y-(-3(y+1))+9-9=0



We calculate terms in parentheses: -(-3(y+1)), so:

-3(y+1)

We multiply parentheses

-3y-3

Back to the equation:

-(-3y-3)



We add all the numbers together, and all the variables

15y-(-3y-3)=0

We get rid of parentheses

15y+3y+3=0

We add all the numbers together, and all the variables

18y+3=0

We move all terms containing y to the left, all other terms to the right

18y=-3

y=-3/18

y=-1/6

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