3y-7=8-3(y+12)

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Solution for 3y-7=8-3(y+12) equation:



3y-7=8-3(y+12)
We move all terms to the left:
3y-7-(8-3(y+12))=0
We calculate terms in parentheses: -(8-3(y+12)), so:
8-3(y+12)
determiningTheFunctionDomain -3(y+12)+8
We multiply parentheses
-3y-36+8
We add all the numbers together, and all the variables
-3y-28
Back to the equation:
-(-3y-28)
We get rid of parentheses
3y+3y+28-7=0
We add all the numbers together, and all the variables
6y+21=0
We move all terms containing y to the left, all other terms to the right
6y=-21
y=-21/6
y=-3+1/2

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