3y-7=5(2y-3)+4=

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Solution for 3y-7=5(2y-3)+4= equation: 



3y-7=5(2y-3)+4=

We move all terms to the left:

3y-7-(5(2y-3)+4)=0



We calculate terms in parentheses: -(5(2y-3)+4), so:

5(2y-3)+4

We multiply parentheses

10y-15+4

We add all the numbers together, and all the variables

10y-11

Back to the equation:

-(10y-11)



We get rid of parentheses

3y-10y+11-7=0

We add all the numbers together, and all the variables

-7y+4=0

We move all terms containing y to the left, all other terms to the right

-7y=-4

y=-4/-7

y=4/7

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