3y-7(4+y)=21

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Solution for 3y-7(4+y)=21 equation: 



3y-7(4+y)=21

We move all terms to the left:

3y-7(4+y)-(21)=0

We add all the numbers together, and all the variables

3y-7(y+4)-21=0

We multiply parentheses

3y-7y-28-21=0

We add all the numbers together, and all the variables

-4y-49=0

We move all terms containing y to the left, all other terms to the right

-4y=49

y=49/-4

y=-12+1/4

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