3y-6+2(2y+1)=-3(y+4)

Solution for 3y-6+2(2y+1)=-3(y+4) equation:

3y-6+2(2y+1)=-3(y+4)

We move all terms to the left:

3y-6+2(2y+1)-(-3(y+4))=0

We multiply parentheses

3y+4y-(-3(y+4))+2-6=0


We calculate terms in parentheses: -(-3(y+4)), so:

-3(y+4)

We multiply parentheses

-3y-12

Back to the equation:

-(-3y-12)


We add all the numbers together, and all the variables

7y-(-3y-12)-4=0

We get rid of parentheses

7y+3y+12-4=0

We add all the numbers together, and all the variables

10y+8=0

We move all terms containing y to the left, all other terms to the right

10y=-8

y=-8/10

y=-4/5