3y-5y-(2y-6)=8y-2(4y-6)

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Solution for 3y-5y-(2y-6)=8y-2(4y-6) equation: 



3y-5y-(2y-6)=8y-2(4y-6)

We move all terms to the left:

3y-5y-(2y-6)-(8y-2(4y-6))=0

We add all the numbers together, and all the variables

-2y-(2y-6)-(8y-2(4y-6))=0

We get rid of parentheses

-2y-2y-(8y-2(4y-6))+6=0



We calculate terms in parentheses: -(8y-2(4y-6)), so:

8y-2(4y-6)

We multiply parentheses

8y-8y+12

We add all the numbers together, and all the variables

12

Back to the equation:

-(12)



We add all the numbers together, and all the variables

-4y-6=0

We move all terms containing y to the left, all other terms to the right

-4y=6

y=6/-4

y=-1+1/2

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