3y-5=2(3-y)

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Solution for 3y-5=2(3-y) equation: 



3y-5=2(3-y)

We move all terms to the left:

3y-5-(2(3-y))=0

We add all the numbers together, and all the variables

3y-(2(-1y+3))-5=0



We calculate terms in parentheses: -(2(-1y+3)), so:

2(-1y+3)

We multiply parentheses

-2y+6

Back to the equation:

-(-2y+6)



We get rid of parentheses

3y+2y-6-5=0

We add all the numbers together, and all the variables

5y-11=0

We move all terms containing y to the left, all other terms to the right

5y=11

y=11/5

y=2+1/5

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