3y-42=6(y-5)

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Solution for 3y-42=6(y-5) equation: 



3y-42=6(y-5)

We move all terms to the left:

3y-42-(6(y-5))=0



We calculate terms in parentheses: -(6(y-5)), so:

6(y-5)

We multiply parentheses

6y-30

Back to the equation:

-(6y-30)



We get rid of parentheses

3y-6y+30-42=0

We add all the numbers together, and all the variables

-3y-12=0

We move all terms containing y to the left, all other terms to the right

-3y=12

y=12/-3

y=-4

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