3y-4(y-2)=19-3(y-2)

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Solution for 3y-4(y-2)=19-3(y-2) equation: 



3y-4(y-2)=19-3(y-2)

We move all terms to the left:

3y-4(y-2)-(19-3(y-2))=0

We multiply parentheses

3y-4y-(19-3(y-2))+8=0



We calculate terms in parentheses: -(19-3(y-2)), so:

19-3(y-2)

determiningTheFunctionDomain
-3(y-2)+19

We multiply parentheses

-3y+6+19

We add all the numbers together, and all the variables

-3y+25

Back to the equation:

-(-3y+25)



We add all the numbers together, and all the variables

-1y-(-3y+25)+8=0

We get rid of parentheses

-1y+3y-25+8=0

We add all the numbers together, and all the variables

2y-17=0

We move all terms containing y to the left, all other terms to the right

2y=17

y=17/2

y=8+1/2

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