3y-30-(y+28)=3y-(2y-4)

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Solution for 3y-30-(y+28)=3y-(2y-4) equation: 



3y-30-(y+28)=3y-(2y-4)

We move all terms to the left:

3y-30-(y+28)-(3y-(2y-4))=0

We get rid of parentheses

3y-y-(3y-(2y-4))-28-30=0



We calculate terms in parentheses: -(3y-(2y-4)), so:

3y-(2y-4)

We get rid of parentheses

3y-2y+4

We add all the numbers together, and all the variables

y+4

Back to the equation:

-(y+4)



We add all the numbers together, and all the variables

2y-(y+4)-58=0

We get rid of parentheses

2y-y-4-58=0

We add all the numbers together, and all the variables

y-62=0

We move all terms containing y to the left, all other terms to the right

y=62

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